I teach my students to calculate the axle load of trucks with the formula; LV=(Lxw)/w and LA= (Lxa)/w .LV is the load on the front axle LA on the rear axle and L is the load. W = the wheelbase. a = distance center of load to front axle, b = center of load to rear axle. A and b together are always W. This works flawlessly with two axes. If axles are closer to each other than 180cm, they legally count as 1 axle. (see drawing WT) But how do you calculate this for a truck with multiple axles. See example.
Cargo box (BL) = 640. So the center load is 320 with an even load. Front loading box to front axle is AC + CB (88+19)=107cm. a = so 427, b must then be 640-427=213. However, if I calculate b using the rear overhang (AE), then b is 65cm (320-255) in front of the rear axle?
If I load this truck to the maximum (25393kg), what will the front axle pressures be?
Answer
Something is not right with the data. When I look at the figure (it’s not very clear), I see that
AC+CB+BL=WB+AE
This is the distance from the front wheel of the truck to the very back.
AC = 88, CB = 19, BL = 640, so together 758.
WB = 640, AE = 255, together 895.
So the data does not match the figure, no one can make that truck.
Answered by
Professor Walter Lauriks
Physics Acoustics
Old Market 13 3000 Leuven
https://www.kuleuven.be/
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