I teach my students to calculate the axle load of trucks with the formula; LV=(Lxw)/w and LA= (Lxa)/w .LV is the load on the front axle LA on the rear axle and L is the load. W = the wheelbase. a = distance h

I teach my students to calculate the axle load of trucks with the formula; LV=(Lxw)/w and LA= (Lxa)/w .LV is the load on the front axle LA on the rear axle and L is the load. W = the wheelbase. a = distance center of load to front axle, b = center of load to rear axle. A and b together are always W. This works flawlessly with two axes. If axles are closer to each other than 180cm, they legally count as 1 axle. (see drawing WT) But how do you calculate this for a truck with multiple axles. See example.

Cargo box (BL) = 640. So the center load is 320 with an even load. Front loading box to front axle is AC + CB (88+19)=107cm. a = so 427, b must then be 640-427=213. However, if I calculate b using the rear overhang (AE), then b is 65cm (320-255) in front of the rear axle?

If I load this truck to the maximum (25393kg), what will the front axle pressures be?

Asker: Bart, 49 years old

Answer

Something is not right with the data. When I look at the figure (it’s not very clear), I see that

AC+CB+BL=WB+AE

This is the distance from the front wheel of the truck to the very back.

AC = 88, CB = 19, BL = 640, so together 758.

WB = 640, AE = 255, together 895.

So the data does not match the figure, no one can make that truck.

Answered by

Professor Walter Lauriks

Physics Acoustics

Catholic University of Leuven
Old Market 13 3000 Leuven
https://www.kuleuven.be/

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