Asker: Laura, age 35
Answer
If we neglect the relief on the moon :
The gravitational acceleration at the lunar surface is GM / R2 where M and R are the mass and radius of the moon.
The centrifugal acceleration in a circular orbit is v2 / R, with v being the speed.
If we want to make a bullet fly in a circular orbit just above the moon’s surface, those two accelerations must neutralize each other. Gravitation is downward, centrifugal acceleration upward. By equating the two sizes, we find the required speed.
With G = 6.6727 10-11 Nm2/ kg2R = 1.738 106 m and M = 7.35 1022 kg
from which : v = 1680 m/s
Answered by
prof.dr. Paul Hellings
Department of Mathematics, Fac. IIW, KU Leuven
Catholic University of Leuven
Old Market 13 3000 Leuven
https://www.kuleuven.be/
Old Market 13 3000 Leuven
https://www.kuleuven.be/
.