Four drippers in a greenhouse give, measured with a chronometer at 03:06.70, 0.5 liters of water. At a stop on the chronometer at 00:41.77 I have 0.6 liters of water and at 00:38.61 I get 0.7 liters of water. How do I calculate the minutes with 0.6 and 0.7 liters of water respectively? So I want to count the intermediate times together.
Answer
Dear Johan,
Your question is rather unclear, but I think you mean that your stopwatch should show a time of 3:06.70 + 00:41.77 = 3:48.47 at 0.6 liters of water, and at 0.7 liters water a time of 3:48.47 + 00:38.61 = 4:27.08.
Is that what you mean? If not, it’s best to ask the question again, but worded better. I also find, given the (in)accuracy to read the amount of water, that it is quite useless to calculate with hundredths of a second.
Regards,
Hendrik Van Maldeghem
Answered by
prof. Hendrik Van Maldeghem
Mathematics, geometry, algebra
http://www.ugent.be
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