In this reaction equation (redox reaction) 2 CuO + C –> 2 Cu + CO2
based on OG you get the following:
For the arrow: OG (Cu) = + II , OG (O) = – II , OG (C) = 0
After the arrow: OG (Cu) = 0 , OG (C) = + IV , OG (O) = – II
From this concludes ==>
Reduction of CuO to Cu
Oxidation of C to CO2
But then comes my question; if I now ask which substance is the oxidizer : is the answer CuO or Cu?
Answer
Hi Jens,
The oxidizer is the product that reduces (CuO : Cu2+ + 2nd– -> Cu°)
Cu 2+ must take up 2 electrons. These electrons come from C, which starts to oxidize by donating electrons.
C – 4th– -> C4+
Conclusion: The product that reduces can oxidize another = oxidizer or/ oxidant (CuO)
The product that oxidizes can reduce another = reductant or reductant (C)
I hope I could help you with this,
Regards,
Gerda Dewulf
Answered by
lic sciences – chemistry Gerda Dewulf
organic chemistry
Brothers De Smetstraat 1 9000 Ghent
http://www.odisee.be
.